5x^2+10x+330=540

Solution for 5x^2+10x+330=540 equation:

5x^2+10x+330=540

We move all terms to the left:

5x^2+10x+330-(540)=0

We add all the numbers together, and all the variables

5x^2+10x-210=0

a = 5; b = 10; c = -210;
Δ = b2-4ac
Δ = 102-4·5·(-210)
Δ = 4300
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{4300}=\sqrt{100*43}=\sqrt{100}*\sqrt{43}=10\sqrt{43}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-10\sqrt{43}}{2*5}=\frac{-10-10\sqrt{43}}{10}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+10\sqrt{43}}{2*5}=\frac{-10+10\sqrt{43}}{10}
$